Collections frequency ,reverse order and sort.

This  program  is  solve  most   trick  interview question  may be asked  while you  face
java developer position  in  any  software development company .It  to understands  the
 program .please go through  it.



import java.util.*;


public class CollOrder {

public static void main(String[] args) {
// TODO Auto-generated method stub
 List  mylist=new  ArrayList();
 
         mylist.add(5);
         mylist.add(6);
         mylist.add(8);
         mylist.add(8);
         mylist.add(1);
         mylist.add(2);
         mylist.add(5);
         mylist.add(5);
        
      System.out.println("Current List");
      
        System.out.println(mylist);
      
      System.out.println("Reverse of added number");
       Collections.reverse(mylist);
        
      System.out.println(mylist);
      
      
        
        
         System.out.println("List after sorting "); 
         Collections.sort(mylist);
         for(int i: mylist){
         
       
           System.out.println( +i);
         
         }
        
        Comparator cmp=Collections.reverseOrder();
    
        Collections.sort(mylist ,cmp);
        System.out.println("List  reverse order ");
        for(int i: mylist){
         
       
           System.out.println( +i);
         
         
        }
          
       System.out.println(" Frequency of the repeated element"); 
      int i= Collections.frequency(mylist, 8);
      int fi= Collections.frequency(mylist, 5);
          System.out.println("frequency of 8::"+i);
          System.out.println("frequency of 5::"+fi);
}

}


Program  output :


Current List
[5, 6, 8, 8, 1, 2, 5, 5]
Reverse of added number
[5, 5, 2, 1, 8, 8, 6, 5]
List after sorting
1
2
5
5
5
6
8
8
List  reverse order
8
8
6
5
5
5
2
1
 Frequency of the repeated  element
frequency of 8::2
frequency of 5::3